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Giacomo Balli
Innovation consultant specializing in mobile strategy
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Get all pages of paginated API Response

Get All Pages Of API

This code sample will allow you to iterate API calls when pagination is in place.

allResults=[];
currApiPage=1;
function getAllPages() {
	var url="http://google.com/API/search"+"?page="+currApiPage;
	var req = new XMLHttpRequest();
	req.open("GET",url,true);
	req.onload = function(evt){
		var resp=JSON.parse(evt.target.responseText);
		for (var i = 0; i < r.results.length; i++) {
            allResults.push(r.results[i]);
        }
        if (r.has_next) {
            currApiPage++;
            getAllPages();
        } else {
            currApiPage = 1;
        }
	}
	req.send(null);
}

Directions:
- replace http://google.com/API/search with your API url
- replace r.results with the array in your own JSON response
- usually when initializing your project, call getAllPages()

Note:
This snippet focuses on iOS development. Make sure to verify/adapt any vendor prefixes. Back to main listing.

Published: Mon, 11 Jan 2016 02:55:35 +0000